5x^2+38x+36=0

Solution for 5x^2+38x+36=0 equation:

5x^2+38x+36=0

a = 5; b = 38; c = +36;
Δ = b2-4ac
Δ = 382-4·5·36
Δ = 724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{724}=\sqrt{4*181}=\sqrt{4}*\sqrt{181}=2\sqrt{181}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-2\sqrt{181}}{2*5}=\frac{-38-2\sqrt{181}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+2\sqrt{181}}{2*5}=\frac{-38+2\sqrt{181}}{10}
$